Area of sectors and segments
Mensuration · Mathematics
Study notes
Q: r = 10, central angle 90°. Sector area? Segment area? Sector: 90/360 × π×100 = 25π ≈ 78.54. Triangle (right isosceles): 10×10/2 = 50. Minor segment: 25π - 50 ≈ 28.54. Major segment: 100π - 28.54 ≈ 285.62!