Q: Graph x + 2y <= 6, x >= 0, y >= 0. Find the feasible region's corners. Step 1: Boundary: x + 2y = 6. Intercepts: (6, 0), (0, 3). Step 2: Test (0,0): 0 <= 6 true, so shade toward origin. Step 3: x >= 0, y >= 0 restrict to first quadrant. Step 4: Feasible region: triangle with corners (0,0), (6,0), (0,3).