Q: Find the maxima/minima of f(x) = x^3 - 3x^2. f'(x) = 3x^2 - 6x = 3x(x-2). Critical: x=0, 2. f''(x) = 6x - 6. f''(0) = -6 < 0: local max at x=0, f=0. f''(2) = 6 > 0: local min at x=2, f=-4.