Q: Solve: (a) 2cos x - 1 = 0 on [0,2π) (b) sin²x - sin x = 0 generally. (a) cos x = 1/2: x = π/3, 5π/3. (b) sin x(sinx - 1) = 0: sinx = 0 → x = nπ; sinx = 1 → x = 2nπ + π/2.