Binding energy of satellites
Universal gravitation · Physics
Solar system
Interactive 3DAll eight planets in orbit around the Sun, with Saturn's rings and Earth's Moon.
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A 1000-kg satellite orbits Earth at a height of 1000 km above the surface. Find its binding energy. (R = 6.37 × 10⁶ m, g = 9.8 m/s²) Step 1: Orbital radius r = R + h = 6.37 × 10⁶ + 1.0 × 10⁶ = 7.37 × 10⁶ m. Step 2: Binding energy = GMm/(2r). Use GM = gR² = 9.8 × (6.37 × 10⁶)² = 3.976 × 10¹⁴ m³/s². Step 3: BE = (3.976 × 10¹⁴ × 1000) / (2 × 7.37 × 10⁶) = 3.976 × 10¹⁷ / 1.474 × 10⁷ ≈ 2.70 × 10¹⁰ J. Answer: ≈ 2.7 × 10¹⁰ J (27 GJ). That is the energy of about 6.5 tonnes of TNT — freeing a satellite takes an enormous punch, which is why dead satellites stay up there.
Related topics
- Kepler's laws of planetary motion
- Newton's universal law of gravitation
- Gravitational constant and its measurement (Cavendish experiment)
- Acceleration due to gravity and its variation (altitude, depth, rotation of Earth)
- Gravitational field and field intensity
- Gravitational potential and potential energy