Energy of orbiting satellites
Universal gravitation · Physics
Solar system
Interactive 3DAll eight planets in orbit around the Sun, with Saturn's rings and Earth's Moon.
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A 500-kg satellite moves in a circular orbit of radius 8.0 × 10⁶ m around Earth. Find its KE, PE and total energy. (GM = 3.98 × 10¹⁴ m³/s²) Step 1: KE = GMm/(2r) = (3.98 × 10¹⁴ × 500) / (2 × 8.0 × 10⁶) = 1.99 × 10¹⁷ / 1.6 × 10⁷ = 1.24 × 10¹⁰ J. Step 2: PE = −GMm/r = −2 × KE = −2.49 × 10¹⁰ J. Step 3: E = KE + PE = 1.24 × 10¹⁰ − 2.49 × 10¹⁰ = −1.24 × 10¹⁰ J = −KE. Answer: KE ≈ +1.24 × 10¹⁰ J, PE ≈ −2.49 × 10¹⁰ J, E ≈ −1.24 × 10¹⁰ J. The negative total confirms the satellite is bound to Earth.
Related topics
- Kepler's laws of planetary motion
- Newton's universal law of gravitation
- Gravitational constant and its measurement (Cavendish experiment)
- Acceleration due to gravity and its variation (altitude, depth, rotation of Earth)
- Gravitational field and field intensity
- Gravitational potential and potential energy