A transformer has 200 turns in the primary and 1000 turns in the secondary. The primary is connected to 220 V AC and draws 5 A. Assuming an ideal transformer, find (a) the secondary voltage, (b) the secondary current, (c) the power delivered. Step 1: Voltage ratio Vs/Vp = Ns/Np = 1000/200 = 5. So Vs = 5 × 220 = 1100 V. This is a step-up transformer. Step 2: For an ideal transformer, power in = power out: VpIp = VsIs. Input power = 220 × 5 = 1100 W. So Is = 1100/1100 = 1.0 A. (Check: Is/Ip = Np/Ns = 200/1000 = 1/5, and 5 × 1/5 = 1 A ✓.) Step 3: Power delivered to the load = Vs × Is = 1100 × 1.0 = 1100 W. In a real transformer with, say, 96% efficiency, the output would be 0.96 × 1100 = 1056 W, with 44 W lost as copper, eddy-current, hysteresis and leakage losses.