Fiber optics: total internal reflection, types of fibers
Engineering Physics · Engineering
Study notes
A fiber has core n₁ = 1.48, cladding n₂ = 1.46. Find critical angle and NA. θc = sin⁻¹(1.46/1.48) = sin⁻¹(0.9865) ≈ 80.6°. NA = √(1.48² − 1.46²) = √(2.1904 − 2.1316) = √0.0588 ≈ 0.242. Acceptance angle ≈ 14°.
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