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Equation of a plane

Three-dimensional geometry and vector algebra · Mathematics

Study notes

Q: Find the plane through (1,0,0), (0,2,0), (0,0,3). Intercept form: x/1 + y/2 + z/3 = 1. Multiply by 6: 6x + 3y + 2z = 6. Normal n = (6,3,2).

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