Laws of exponents
Number systems · Mathematics
Study notes
Q: Simplify (2x³)² × x⁻¹ and (a²b³)⁰. Step 1: (2x³)² = 2² × (x³)² = 4x⁶. Step 2: 4x⁶ × x⁻¹ = 4x^(6−1) = 4x⁵. Step 3: (a²b³)⁰ = 1 (anything nonzero to power 0 is 1).
One notebook for every subject — open it anywhere.
Number systems · Mathematics
Q: Simplify (2x³)² × x⁻¹ and (a²b³)⁰. Step 1: (2x³)² = 2² × (x³)² = 4x⁶. Step 2: 4x⁶ × x⁻¹ = 4x^(6−1) = 4x⁵. Step 3: (a²b³)⁰ = 1 (anything nonzero to power 0 is 1).