Rate of change of quantities
Differentiation · Mathematics
Study notes
Q: A spherical balloon's radius grows at 2 cm/s. How fast is the volume growing when r = 5 cm? V = (4/3)πr^3. dV/dt = 4πr^2 * dr/dt. At r=5: dV/dt = 4π(25)(2) = 200π cm^3/s.
One notebook for every subject — open it anywhere.
Differentiation · Mathematics
Q: A spherical balloon's radius grows at 2 cm/s. How fast is the volume growing when r = 5 cm? V = (4/3)πr^3. dV/dt = 4πr^2 * dr/dt. At r=5: dV/dt = 4π(25)(2) = 200π cm^3/s.