Tangent and normal to a parabola
Two-dimensional geometry · Mathematics
Study notes
Q: Find the tangent and normal to y² = 12x at (3,6). T = 0: y(6) = 6(x+3) → 6y = 6x+18 → y = x+3. Normal: slope = −y₁/2a = −6/6 = −1. Normal: y−6 = −1(x−3) → y = −x+9.