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Torsional pendulum

Simple harmonic motion · Physics

Simple pendulum

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Release the bob and watch true small-angle SHM. The period depends only on the string length.

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m
0.3m2m
°
5°45°

Study notes

Problem: A metal disk with a moment of inertia of 0.05 kg·m² is suspended by a wire. The wire has a torsional constant of 0.02 N·m/rad. Calculate the time period of oscillation. Step 1: Identify the formula for the time period of a torsional pendulum: T = 2π√(I/k), where I is the moment of inertia and k is the torsional constant. Step 2: Substitute the given values into the formula. I = 0.05 kg·m² and k = 0.02 N·m/rad. Step 3: Calculate the ratio I/k. 0.05 / 0.02 = 2.5. Step 4: Take the square root of the result. √2.5 ≈ 1.581. Step 5: Multiply by 2π. 2 * 3.14159 * 1.581 ≈ 9.93 seconds. Answer: The time period of oscillation is approximately 9.93 seconds.

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