Let's calculate 5 + 3 using the 8085 logic. Step 1: The processor loads the number 5 into the Accumulator (A register). So, A = 5. Step 2: The processor loads the number 3 into a temporary register, let's say B. So, B = 3. Step 3: The ALU is told to add the value in A and the value in B. It performs the addition: 5 + 3 = 8. Step 4: The result, 8, is stored back into the Accumulator (A). So, A = 8. Step 5: The processor checks the flags. Since the result is not zero, the Zero flag is off. Since there is no carry over (8 is less than 16 in hex, or simply fits in 8 bits), the Carry flag is off. The calculation is complete.