Area under a simple curve
Applications of integration · Mathematics
Study notes
Q: Find the area under y = x^2 from x = 0 to x = 2. Area = integral 0 to 2 of x^2 dx = [x^3/3] 0 to 2 = 8/3. Units: square units. The region is bounded by the curve, the x-axis, x=0, x=2.